Find allgebraiclly the equation of the axis of symmetry and the vertex of the parabola represented by the equation y=-x2-2x+1

To find the vertex use - b/2a (for the x value which is also the axis of symmetry)

So 2/-2 = - 1 Therefore the axis of symmetry is x=-1 Plug in for the y value:

y = - (-1) ^2 - 2 (-1) + 1 y=-1 + 2 + 1 y=2 Vertex (-1,2)