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19 December, 17:52

What are the zeros of the function

f (x) = x^2-5x-24

+3
Answers (2)
  1. 19 December, 17:58
    0
    We need to put this in factored form. I can explain factored form if you want, but for now I’ll just show you the result.

    (X-8) (x+3)

    We can check if this is the right equation.

    X^2 + 3x-8x-24

    So, we have the factored form and it will be very easy to find the zeros.

    (X-8) (x+3)

    We need for that to equal zero. Whenever you multiply anything by y zero, you’ll receive zero.

    X=8, x=-3

    They will satisfy the equation and will get you zero. Let’s check.

    8^2-5 (8) - 24

    64-40-24

    24-24

    0

    So 8 works.

    -3^2-5 (-3) - 24

    9+15-24

    24-24

    0

    So, the zeros are 8 and - 3.
  2. 19 December, 18:10
    0
    8 and - 3

    Start by factoring the equation:

    (x + 3) (x - 8)

    Then set each equal to zero and solve for each one.
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