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6 December, 16:42

Find the limit

lim 5tan^-1 (ln3x)

x>infinity

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Answers (1)
  1. 6 December, 17:03
    0
    Lim ln (3x) = ∞ as x->∞

    tan^ (-1) (∞ ) = π (k+1/2) where k is an integer.

    Therefore

    lim 5tan^ (-1) (ln (3x)) = 5 (k+1/2) π as x-> ∞ and where k∈ Z (i. e. integers)
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