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20 October, 16:35

What is the vertex of the function x^2-6x+8=0?

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  1. 20 October, 17:00
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    -6 / 2 = - 3 so

    x^2 - 6x + 8 is

    (x - 3) ^2 - 9 + 8

    = (x - 3) ^2 - 1

    the vertex is at (3,-1)
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