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Layla
Mathematics
20 October, 16:35
What is the vertex of the function x^2-6x+8=0?
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Shawn Carlson
20 October, 17:00
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-6 / 2 = - 3 so
x^2 - 6x + 8 is
(x - 3) ^2 - 9 + 8
= (x - 3) ^2 - 1
the vertex is at (3,-1)
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