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If the sum of three consecutive even integers is 192, what is the first of the three integers?

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  1. 29 May, 06:11
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    Smallest:x-2

    middle:x

    biggest:x+2

    smallest+middle=biggest = (x-2) + (x) + (x+2) = 3x

    3x=192->3x/3=192/3->x=64

    smallest: 64-2=62
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