The sum of 3 consecutive odd integers is 18 less than five times the middle number. Find the three integers

n, n + 2, n + 4 - three consecutive odd ntegers

n + (n + 2) + (n + 4) = 5 (n + 2) - 18 |use distributive property

n + n + 2 + n + 4 = (5) (n) + (5) (2) - 18

3n + 6 = 5n + 10 - 18

3n + 6 = 5n - 8 |subtract 6 from both sides

3n = 5n - 14 |subtract 5n from both sides

-2n = - 14 |divide both sides by (-2)

n = 7

n + 2 = 7 + 2 = 9

n + 4 = 7 + 4 = 11

Answer: 7, 9, 11.