Soybean mean is 14% protein; cornmeal is 7% protein. How many pounds of each should be mixed together in order to get 280-lb mixture that is 13% protein?

I have to form a couple of equations in order to solve it.

let the amount of soybean in the mixture be x and that of cornmeal be y

Step-by-step explanation:

x+y = 280

y = 280 - x

x * (14/100) + y * (7/100) = 280 * (12/100)

Multiplying the whole equation by 100;

14x + 7y = 3360

in this equation, put y = 280 - x

14x + 7 (280-x) = 3360

14x + 1960 - 7x = 3360

14x - 7x = 3360 - 1960

7x = 1400

x = 200lbs

y = 280 - x

= 280 - 200

= 80 lbs

Inorder to make a 280lbs mixture having 12% protein, we should mix 200lbs of soyabean and 80 lbs of cornmeal