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Sonny
Mathematics
30 December, 11:52
This equation: (y-3) ^2=4y-12
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Shelton
30 December, 11:59
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(y-3) ^2 = 4y-12
(y-3) (y-3) = 4y-12
y^2-6y+9 = 4y-12
y^2-10y+21 = 0
(y-3) (y-7) = 0
y = 3, 7
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