A gardener is going to plant 2 red rosebushes and 2 white rosebushes. If the gardener is to select each of the bushes at random, one at a time, and plant them in a row, what is the probability that the 2 rosebushes in the middle of the row will be the red rosebushes?

The answer to the question is

The probability that the 2 rosebushes in the middle of the row will be the red rosebushes = 1/6

Step-by-step explanation:

To solve the question we note that the required permutation is WRRW

Therefore the total number of ways to plant the four rose bushes given that two white rose bushes are in the middle is given by

4! / (2!2!) = 6 Therefore the probability that the 2 rosebushes in the middle of the row will be the red rosebushes = 1/6

16.66%

Step-by-step explanation:

The probability would be the multiplication of the different events.

First event, take out a white rose and plant it, the probability of that is 2/4 = 1/2

Second event, take out a red rose and plant it, the probability is 2/3.

Third event, take out another red rose and plant it, the probability is 1/2.

Now, the probability of everything is:

(1/2) * (2/3) * (1/2) = 0.166

that is to say, the probability of what the statement asks us to happen is 16.66%