Enter the expression 2cos2 (θ) - 1, where θ is the lowercase Greek letter theta. 2cos2 (θ) - 1 2 c o s 2 (θ) - 1 = nothing

Question

Guest

Mathematics

31 March, 14:31

Enter the expression 2cos2 (θ) - 1, where θ is the lowercase Greek letter theta. 2cos2 (θ) - 1 2 c o s 2 (θ) - 1 = nothing

+3

Answers (1)

Know the Answer?

Leroy Cunningham · Answer 1

We have to evaluate

=2 cos 2 Ф - 1

⇒cos 2 Ф

A = 2cos²Ф-1

B = 1 - 2 sin²Ф

C = cos²Ф - sin²Ф

Possible Answers are

1.

=2 * (2cos²Ф-1) - 1

=4cos²Ф-2-1

=4cos²Ф - 3

2.

=2 * (1 - 2 sin²Ф) - 1

=2 - 4sin²Ф-1

=1 - 4sin²Ф

3.

=2 * (cos²Ф - sin²Ф) - 1

=2 cos²Ф - 2sin²Ф-1