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3 May, 04:25

What are the foci of the hyperbola with the equation 25x^2-4y^2=400

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  1. 3 May, 04:44
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    25x²-4y²=400

    (x-h) ²/a² - (y-k) ²/b²=1

    (5x) ² - (2y) ²=400

    (x) ²/16 - (y) ²/100 = 1

    a²+b²=c²

    16+100=c²

    c²=116

    c=-+√116

    foci are (-√116,0) and (√116,0)
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