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12 May, 23:30

Twice a number increased by 3 is less than the number decreased by 4

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  1. 12 May, 23:55
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    Set it up like this: 2n+3 < n-4

    Solve for n:

    2n+3 < n-4

    -n - n (1st step: get n on one side by itself)

    n+3 < - 4

    -3 - 3 (2nd step: subtract 3 from both sides)

    n < - 7

    The answer is n < - 7
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