Twice a number increased by 3 is less than the number decreased by 4

Set it up like this: 2n+3 < n-4

Solve for n:

2n+3 < n-4

-n - n (1st step: get n on one side by itself)

n+3 < - 4

-3 - 3 (2nd step: subtract 3 from both sides)

n < - 7

The answer is n < - 7