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5 June, 20:19

Create a pattern with the rule n*2+1

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  1. 5 June, 20:25
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    The rule (n*2+1) gives the sequence of odd numbers { ..., - 5, - 3, - 1, 1, 3, 5, ... }.

    Step-by-step explanation:

    We have the expression 'n*2+1'.

    It is required to find a pattern obtained by the expression.

    Substituting values of 'n' gives,

    For n = - 3, we get (n*2+1) = (-3*2+1) = - 6+1 = - 5

    For n = - 2, we get (n*2+1) = (-2*2+1) = - 4+1 = - 3

    For n = - 1, we get (n*2+1) = (-1*2+1) = - 2+1 = - 1

    For n = 0, we get (n*2+1) = (0*2+1) = 1

    For n = 1, we get (n*2+1) = (1*2+1) = 2+1 = 3

    For n = 2, we get (n*2+1) = (2*2+1) = 4+1 = 5

    So, we see that, substituting the value of n, the result comes out to be an odd number.

    Hence, the rule (n*2+1) gives the sequence of odd numbers { ..., - 5, - 3, - 1, 1, 3, 5, ... }.
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