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25 January, 00:12

Find the positive value of k such that the area of the region enclosed between the graph y=kcosx and the graph y=kx^2 is 2

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  1. 25 January, 00:18
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    Both these graphs will pass through the origin so you need to work out the difference in areas by integrating

    INtegral k cos x (between the limits 0 and a) - Intgral kx^2 (between 0 and a) = 2

    Find k

    (where a is the value of x on positive side of the graph where the 2 curves intersect)
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