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27 February, 05:53

Find the reminder of the division

(8^33) : 6

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  1. 27 February, 06:16
    0
    The remainder is 2.

    Step-by-step explanation:

    Use modular arithmetic.

    If the remainder is x then 8^33 mod 6 = x.

    8^3 = 512 = 2 mod 6

    8^6 = (8^3 * 8^3) mod 6 = (2*2) mod 6 = 4 mod 6

    8^30 mod 6 = (8^6) ^5 mod 6 = 4^5 mod 6 = 1024 mod 6

    = 4 mod 6.

    Finally 8^33 mod 6 = (8^3 * 8^30) mod 6 = (2 * 4) mod 6

    = 8 mod 6 = 2.
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