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17 June, 02:11

Given: F (x) = 3x ^2 + 1, G (x) = 2x - 3, H (x) = x

H - 1 (x) =

x

1/x

-x

+3
Answers (1)
  1. 17 June, 02:21
    0
    If I understand right you want the inverse of H (x)

    H (x) = x

    y=x

    to calculate the inverse, isolate x, which is already the case, switch x and y, which doesn't change anything and that is your new function

    the inverse is the same function in this case

    so H⁻¹ (x) = x
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