A circle has its center at (-1, 2) and a radius of 3 units. What is the equation of the circle?

A) (x - 1) 2 + (y + 2) 2 = 3

B) (x + 1) 2 + (y - 2) 2 = 3

C) (x + 1) 2 + (y + 2) 2 = 9

D) (x + 1) 2 + (y - 2) 2 = 9

Question

Jon Cline

Mathematics

14 November, 00:24

A circle has its center at (-1, 2) and a radius of 3 units. What is the equation of the circle?

A) (x - 1) 2 + (y + 2) 2 = 3

B) (x + 1) 2 + (y - 2) 2 = 3

C) (x + 1) 2 + (y + 2) 2 = 9

D) (x + 1) 2 + (y - 2) 2 = 9

+5

Answers (1)

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Chiquita · Answer 1

So the question or problem ask to find the equation of a circle which has a center of (-1,2) and a radius of 3 units. To get the equation of the circle, you must first follow the formula which is (x-h) ^2 + (y-k) ^2 = r^2. So the answer would be letter D. (x+1) 2 + (y-2) 2=9. I hope you are satisfied with my answer

A circle has its center at (-1, 2) and a radius of 3 units. What is the equation of the circle?A) (x - 1) 2 + (y + 2) 2 = 3B) (x + 1) 2 + (y - 2) 2 = 3C) (x + 1) 2 + (y + 2) 2 = 9D) (x + 1) 2 + (y - 2) 2 = 9

A circle has its center at (-1, 2) and a radius of 3 units. What is the equation of the circle?

A) (x - 1) 2 + (y + 2) 2 = 3

B) (x + 1) 2 + (y - 2) 2 = 3

C) (x + 1) 2 + (y + 2) 2 = 9

D) (x + 1) 2 + (y - 2) 2 = 9