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14 July, 02:13

What's the inverse of y=4x^2-2

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  1. 14 July, 02:25
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    Interchange the x and y and solve for the resulting y.

    x = 4y^2 - 2

    (x + 2) = 4y^2

    (x + 2) / 4 = y^2

    + / - sqrt (x + 2) / 2 = y

    The graph of these two is below.

    The original is in red

    The inverse is in blue and green
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