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Izabelle
Mathematics
25 July, 13:37
How do you substitute 3x-12y=-6 and x-4=-8?
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Jayda Tate
25 July, 13:52
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x - 4 = - 8 add 4 to both sides
x = - 4
Put the value of x to the first equation 3x - 12y = - 6:
3 (-4) - 12y = - 6
-12 - 12y = - 6 add 12 to both sides
-12y = 6 divide both sides by (-12)
y = - 0.5
Answer: x = - 4 and y = - 0.5
New question:
x - 4y = - 8 add 4y to both sides
x = 4y - 8
Substitute it to the first equation:
3 (4y - 8) - 12y = - 6 use distributive property
(3) (4y) + (3) (-8) - 12y = - 6
12y - 24 - 12y = - 6
-24 = - 6 FALSE
Answer: No solution.
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