The circular bull's-eye of an archery target has a diameter of 24 cm, which is surrounded by 4 concentric rings with a width of 12 cm each. Draw the target in a coordinate plane with center at the origin. Write the equations of the circles that form the boundaries of the different regions of the target.

Question

Ryker Watts

Mathematics

8 November, 02:00

The circular bull's-eye of an archery target has a diameter of 24 cm, which is surrounded by 4 concentric rings with a width of 12 cm each. Draw the target in a coordinate plane with center at the origin. Write the equations of the circles that form the boundaries of the different regions of the target.

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Sydnee Howe · Answer 1

Given:

Target bull's eye with a diameter of 24 centimeters.

4 concentric rings with a width of 12 cm each.

First circle, d1 = 24 cm

2nd circle, d2 = 24 + (12*2) = 48 cm

3rd circle, d3 = 24 + (12*3) = 60 cm

4th circle, d4 = 24 + (12*4) = 72 cm