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6 February, 13:37

The sum of two rational numbers will always be

an irrational number.

an integer.

a rational number.

a whole number.

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Answers (1)
  1. 6 February, 14:06
    0
    I think that the sum will always be a rational number

    let's prove that

    any rational number can be represented as a/b where a and b are integers and b≠0

    and an integer is the counting numbers plus their negatives and 0

    so like - 4,-3,-2,-1,0,1,2,3,4 ...

    so, 2 rational numbers can be represented as

    a/b and c/d (where a, b, c, d are all integers and b≠0 and d≠0)

    their sum is

    a/b+c/d=

    ad/bd+bc/bd=

    (ad+bc) / bd

    to prove that the sum will always be a rational number, we must prove that

    1. the numerator and denomenator will be integers

    2. that the denomenator does not equal 0

    alright

    1.

    we started with that they are all integers

    ab+bc=?

    if we multiply any 2 integers, we get an integer

    like 3*4=12 or - 3*4=-12 or - 3*-4=12, etc

    even 0*4=0, that's an integer

    the sum of any 2 integers is an integer

    lik 4+3=7, 3 + (-4) = - 1, 3+0=3, etc

    so we have established that the numerator is an integer

    now the denomenator

    that is just a product of 2 integers so it is an integer

    2. we originally defined that b≠0 and d≠0 so we're good

    therfor, the sum of any 2 rational numbers will always be a rational number is the correct answer
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