F (x) = x2 + 10

What is the average rate of chan

hange of f over the interval [-2, - 1]?

The average rate of change is given by [f (b) - f (a) ] / (b - a), where a and b represent the interval [a, b].

Let a = - 2

Let b = - 1

[ (-1) ^2 + 10 - ((-2) ^2 + 10) ] / (-1 - (-2))

[1 + 10 - (4 + 10) ] / (-1 + 2)

[1 + 10 - 4 - 10] / (1)

[1 - 4] / (1)

-3/1

Answer: - 3