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11 January, 10:09

Rewrite the equation by completing the square. 4 x^{2} + 20x + 25 = 0

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Answers (2)
  1. 11 January, 10:11
    0
    (2x + 5) ² = 0

    Step-by-step explanation:

    4x² + 20x + 25 = 0

    4x² + 10x + 10x + 25 = 0

    2x (2x + 5) + 5 (2x + 5) = 0

    (2x + 5) (2x + 5) = 0

    (2x + 5) ² = 0
  2. 11 January, 10:33
    0
    (x+5/2) ^2 = 0

    Step-by-step explanation:

    4 x^{2} + 20x + 25 = 0

    Divide by 4

    4/4 x^{2} + 20/4x + 25/4 = 0

    x^2 + 5x + 25/4 = 0

    Subtract 25/4 from each side

    x^2 + 5x + 25/4 - 25/4 = -25/4

    x^2 + 5x = -25/4

    Take the coefficent of x

    5

    Divide by 2

    5/2

    Square it

    25/4

    Add it to each side

    x^2 + 5x + 25/4 = -25/4+25/4

    (x+5/2) ^2 = 0

    Take the square root of each side

    x+5/2 = 0

    x = - 5/2
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