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7 July, 18:29

Write quadratic equation in standard form with given solution set:

{1/6, - 2/3} ... ?

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  1. 7 July, 18:47
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    (x - 1/6) (x - (-2/3)) = 0

    (x - 1/6) (x + 2/3) = 0

    x^2 + 2/3x - 1/6x - 1/6 (2/3) = 0

    x^2 + 1/2x - 1/9 = 0

    18x^2 + 9x - 2 = 0
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