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25 April, 06:10

Find the quotient of the quantity negative 6 times x to the 2nd power times y to the 8th power plus 12 times x times y to the 3rd power minus 36 times x times y to the 2nd power all over 6 times x times y to the 2nd power.

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  1. 25 April, 06:31
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    [ - 6 * x^2 * y^8 + 12 * x * y^3 - 36 * x * y^2 ] / [6*x*y^2] =

    [-6x^2 y^8 ] / [6xy^2] + [12x y^3] / [6xy^2] - [36xy^2] / [6xy^2] =

    - xy^6 + 2y - 6

    Answer: - xy^6 + 2y - 6
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