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30 October, 09:19

Find each product.

1) (3n + 2) (n+3)

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  1. 30 October, 09:32
    0
    3n² + 11n + 6

    Step-by-step explanation:

    Each term in the second factor is multiplied by each term in the first factor, that is

    3n (n + 3) + 2 (n + 3) ← distribute both parenthesis

    = 3n² + 9n + 2n + 6 ← collect like terms

    = 3n² + 11n + 6
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