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Yazmin
Mathematics
Today, 09:19
Find each product.
1) (3n + 2) (n+3)
+4
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1
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Skylar
Today, 09:32
0
3n² + 11n + 6
Step-by-step explanation:
Each term in the second factor is multiplied by each term in the first factor, that is
3n (n + 3) + 2 (n + 3) ← distribute both parenthesis
= 3n² + 9n + 2n + 6 ← collect like terms
= 3n² + 11n + 6
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