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Colin Houston
Mathematics
10 August, 07:45
What is (8-2i) - (5+3i) in complex numbers?
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Clarence Mckee
10 August, 07:49
0
= + (8-2i) - (5+3i)
= + 8-2i - 5-3i
= 8-5 - 2i-3i
= 3 - 5i
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Arely Glover
10 August, 08:11
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(8-2i) - (5+3i) =
8-2i-5-3i=
3-5i
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