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5 November, 02:18

Different dealers may sell the same car for different prices. The sale prices for a particular car are normally distributed with a mean and standard deviation of 26 thousand dollars and 2 thousand dollars, respectively. Suppose we select one of these cars at random. Let X represent the sale price (in thousands of dollars) for the selected car. 1. Find P (26< X<30) You may round your answer to two decimal places

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  1. 5 November, 02:22
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    0.48

    Step-by-step explanation:

    P (26
    This probability can be calculated using normal distribution.

    Here mean=μ=26

    standard deviation=σ=2

    So, P (26
    P (26
    P (26
    Hence P (26
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