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1 January, 04:36

Slove the system of equations y=2x-3 y=x^2-3

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  1. 1 January, 04:56
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    (0, - 3) or (2, 1)

    Since both equations express y in terms of x we can equate them

    x² - 3 = 2x - 3

    subtract 2x from both sides

    x² - 2x - 3 = - 3

    add 3 to both sides

    x² - 2x = 0

    take out a common factor of x

    x (x - 2) = 0

    equate each factor to zero and solve for x

    x = 0 or x - 2 = 0 ⇒ x = 2

    substitute values of x into y = 2x - 3 for corresponding values of y

    x = 0 → y = 0 - 3 = - 3 ⇒ (0, - 3)

    x = 2 → y = 4 - 3 = 1 ⇒ (2, 1)
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