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16 October, 01:40

Which equation has the same solutions as 2x^2+16x-10=0 a) (x+4) ^2=-3 b) (x+4) ^2=-11 c) (x+4) ^2=13 d) (x+4) ^2=21

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  1. 16 October, 02:09
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    2x^2 + 16x - 10 = 0

    2 (x^2 + 8x) - 10 = 0

    2 [ (x + 4) ^2 - 16 ] - 10 = 0

    [ (x + 4) ^2 - 16 - 5 = 0

    (x + 4) ^2 - 21 = 0

    (x + 4) ^2 = 21
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