Ask Question
10 August, 04:07

Find two numbers differing by 46 whose product is as small as possible.

+3
Answers (1)
  1. 10 August, 04:36
    0
    Let the numbers be x and y. They differ by 46. Then x = y + 46.

    Their product is P = xy. Since x = y + 46, P = xy = (y + 46) y, or

    P = y^2 + 46y. You could graph this and then identify the coordinates of the vertex, which would give you the minimum value of P.

    Or you could differentiate P (y) with respect to y, set the result = to 0, and solve for y:

    2y + 46 = 0; y = - 23. x = y + 46, or + 23.

    The vertex of the graph of this parabola represents the minimum value of the product P. It is (23, 46), and 46 is the smallest possible product here.
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “Find two numbers differing by 46 whose product is as small as possible. ...” in 📗 Mathematics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers