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28 October, 23:31

What is the value of r6 + y2 when r = 1 and y=11

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Answers (2)
  1. 28 October, 23:43
    0
    1 (6) = 6

    11 (2) = 22

    6+22 = 28

    You plug and chug.
  2. 28 October, 23:50
    0
    1•6 + 11•2

    6+22

    28 would be the answer
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