4. An airplane at T (80,20) needs to fly to both U (20,60) and V (110,85). What is the shortest possible distance for the trip?

165units

170units

97units

169 units

Distance between T (80, 20) and U (20, 60) = sqrt ((20 - 80) ^2 + (60 - 20) ^2) = sqrt ((-60) ^2 + (40) ^2) = sqrt (3600 + 1600) = sqrt (5200) = 72.11 units

Distance between T (80, 20) and V (110, 85) = sqrt ((110 - 80) ^2 + (85 - 20) ^2) = sqrt ((30) ^2 + (65) ^2) = sqrt (900 + 4225) = sqrt (5125) = 71.59

Distance between U (20, 60) and V (110, 85) = sqrt ((110 - 20) ^2 + (85 - 60) ^2) = sqrt ((90) ^2 + (25) ^2) = sqrt (8100 + 625) = sqrt (8725) = 93.41

Therefore, shortest distance for the trip = 71.59 + 93.41 = 165 units.