The sum of three numbers is 140. The third number is 4 times the first. The first number is 8 less than the second. What are the numbers?

A + b + c = 140 (a = first, b = second, c = third)

c = 4a

a = b - 8, so b = a + 8

so now

a + b + c = 140

a + a + 8 + 4a = 140

6a + 8 = 140

6a = 140 - 8

6a = 132

a = 132/6 = 22

b = a + 8 = 22 + 8 = 30

c = 4a = 4x22 = 88

answer:

a = 22, b = 30, c = 88

a (first number) + b (second number) + c (third number) = 140

c = 4a

a = b - 8, so b = a + 8

Next

a + b + c = 140

a + a + 8 + 4a = 140

6a + 8 = 140

6a = 140 - 8

6a = 132

a = 132/6 = 22

b = a + 8 = 22 + 8 = 30

c = 4a = 4x22 = 88

The answer is:

a = 22, b = 30, c = 88