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Matilda Casey
Mathematics
18 December, 20:10
How do i solve x squared = 4x - 5
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Bartlett
18 December, 20:39
0
x = 2 ±i
Step-by-step explanation:
x^2 = 4x-5
Subtract 4x from each side
x^2 - 4x = 4x-5 - 4x
x^2 - 4x = - 5
Complete the square
Take the coefficient of the x term, divide by 2 and square it
-4/2 = 2 2^2 = 4
Add 4 to each side
x^2 - 4x+4 = - 5 + 4
The left side is (x-coefficient of the x term/2) ^2
(x-2) ^2 = - 1
Take the square root of each side
sqrt ((x-2) ^2) = sqrt (-1)
x-2 = ±i
Add 2 to each side
x-2+2 = 2 ±i
x = 2 ±i
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