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18 December, 20:10

How do i solve x squared = 4x - 5

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  1. 18 December, 20:39
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    x = 2 ±i

    Step-by-step explanation:

    x^2 = 4x-5

    Subtract 4x from each side

    x^2 - 4x = 4x-5 - 4x

    x^2 - 4x = - 5

    Complete the square

    Take the coefficient of the x term, divide by 2 and square it

    -4/2 = 2 2^2 = 4

    Add 4 to each side

    x^2 - 4x+4 = - 5 + 4

    The left side is (x-coefficient of the x term/2) ^2

    (x-2) ^2 = - 1

    Take the square root of each side

    sqrt ((x-2) ^2) = sqrt (-1)

    x-2 = ±i

    Add 2 to each side

    x-2+2 = 2 ±i

    x = 2 ±i
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