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13 May, 18:25

How do i get the answer for this limit limit x to 0 (4^2x-1)

without using direct substitution my work so far is limit x to 0 = (4^2x-1) = (4^2x/4^-1) is it correct?

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  1. 13 May, 18:50
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    Lim 4^ (2x-1)

    x-->0

    = 4^ (2 (0) - 1)

    =4^ (-1)

    =1/4
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