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16 December, 18:35

Given that f (x) = x2 - 3x + 3 and g (x) = the quantity of x minus one, over four, solve for f (g (x)) when x = 5.

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  1. 16 December, 18:48
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    g (x) = the quantity of x minus one, over four

    g (x) = (x-1) / 4

    g (5) = (5-1) / 4

    g (5) = 4/4

    g (5) = 1

    f (x) = x2 - 3x + 3

    f (g (5)) = 1^2 - 3 (1) + 3

    f (g (5)) = 1 - 3 + 3

    f (g (5)) = 1
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