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22 September, 21:27
If Sn=n^2+3 then t10=?
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Saul
22 September, 21:35
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T10 = - 21
Step-by-step explanation:
If Sn=n^2+3 then t10=?
Sn = n²+5
put n=1, 2
S1 = T1 = (1) ²+5
=1+5 = 6
S2 = n²+5
S2 = (2) ²+5
S2=4+5
S2=9
T2 = S2 - S1
T2 = 9-6
T2=3
T10 = a + (n-1) d
where a = 6, d = - 3, n=10
T10 = 6 + (10-1) * -3
T10=6 + (9) * -3
T10=6 + (-27)
T10=6-27
T10 = - 21
Therefore T10 = - 21 ...
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