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22 September, 21:27

If Sn=n^2+3 then t10=?

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  1. 22 September, 21:35
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    T10 = - 21

    Step-by-step explanation:

    If Sn=n^2+3 then t10=?

    Sn = n²+5

    put n=1, 2

    S1 = T1 = (1) ²+5

    =1+5 = 6

    S2 = n²+5

    S2 = (2) ²+5

    S2=4+5

    S2=9

    T2 = S2 - S1

    T2 = 9-6

    T2=3

    T10 = a + (n-1) d

    where a = 6, d = - 3, n=10

    T10 = 6 + (10-1) * -3

    T10=6 + (9) * -3

    T10=6 + (-27)

    T10=6-27

    T10 = - 21

    Therefore T10 = - 21 ...
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