Nathan Draws the 2 rectangles shown below in the sand. The perimeter of rectangle A is 20 inches greater than the perimeter of Rectangle B. The width of Rectangle B is 12 inches. What is the length of Rectangle B?

(Part B):

How much greater is the area of Rectangle A than the rectangle B? Show Or Explain how you got your answer.

Question

Parker

Mathematics

12 August, 11:47

Nathan Draws the 2 rectangles shown below in the sand. The perimeter of rectangle A is 20 inches greater than the perimeter of Rectangle B. The width of Rectangle B is 12 inches. What is the length of Rectangle B?

(Part B):

How much greater is the area of Rectangle A than the rectangle B? Show Or Explain how you got your answer.

+1

Answers (1)

Know the Answer?

Emilee · Answer 1

For part A: make the length less than 12in. For example the length could be 9. For part B: multiply the length and the width to get the area. 9*12=108

Then for rectangle A: add 10 to the length and the width from rectangle B, and multiply those sides. (9+10) (12+10) = 418 so rectangle A is about 4 times greater than rectangle B