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14 October, 00:05

The manager of a baseball team has 15 players to choose from for his nine person batting order. How many different ways can he arrange the players in the lineup. A. 5005. B. 362880. C. 3603600. D. 1816214400

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  1. 14 October, 00:22
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    This is 15P9 Number of permutations of 9 in 15.

    = 15! / (15-9) !

    = 1816214400
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