Solve log x = 2.

it's making me write more but I don't rlly have anything to say

If log x = 2

x = 100

Step-by-step explanation:

Logarithm always has a base and an index. It can be I many forms.

It can be in base 2, 3, 4, 5, and so on.

It is a property of logarithm that if

logarithm of 'a' to base 'b' equals 'x', we write:

log_b (a) = x

Then,

a = b^x.

Usually, when a logarithm is written without a base, it tells us that it is in base 10. Instead of writing a logarithm of x to base 10, we can just write 'log x', it is sufficient to say that it is in base 10.

It can also be in the form of the Napierian Logarithm, 'ln'.

'ln x' is logarithm to base 'e'.

if ln x = 5

Then

x = e^5.

So,

log x = 2

Means logarithm of 'x' to base 10 equals 2.

x = 10^2

= 100

x = 100