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Lucas Callahan
Mathematics
31 December, 04:48
How do I factor this problem?2y2 (y+7) + (y+7)
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Lucas Pugh
31 December, 05:16
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First you distribute the 2y^2 into (y + 7). 2y^2 x y = 2y^3 and 2y^2 x 7 = 14y^2. The extra (y + 7) can't be added or multiplied by anything because you can't add y with different exponents. Answer is 2y^3 + 14y^2 + y + 7.
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