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26 August, 12:16

On a particular night, a baseball stadium sells 60% of its seats, and of those, 15% do not end up showing up to the game. Assuming everyone present is sitting in a seat, what percentage of seats in the stadium are empty?

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  1. 26 August, 12:22
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    Step-by-step explanation:

    so llets find what 15% of 60% really is,

    0.15*0.60=0.09

    0.09 AKA 9%

    so since 9% of people didn't show up we can subtract 9% from 60%

    so 60-9=51

    51% of setas are taken

    to find the percent of seats still empty, subtract 100 form 51

    so

    100-51=49

    49% of seats are still empty

    Hope this helsp!
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