Natalie kicked a soccer ball. The equation h=-16t^2+50t describes the height of the ball (T) seconds after it was kicked. Approximately how many seconds went by before the ball hit the ground?

Question

Lainey Patrick

Mathematics

20 January, 17:31

Natalie kicked a soccer ball. The equation h=-16t^2+50t describes the height of the ball (T) seconds after it was kicked. Approximately how many seconds went by before the ball hit the ground?

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Answers (1)

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Aydan Johnson · Answer 1

25/8 or 3.125 seconds

Step-by-step explanation:

To determine the time until the ball hits the ground, you need to solve the quadratic as the height equals zero.

0 = - 16t^2+50t

This gives us a classing quadratic that you can factor or use the quadratic formula to solve.

x = 0, x = 25/8

If you graph this, think of y = 0 as the ground, so when the parabola intersects the x-axis on the right that represents how much time would have passed.