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Mathematics
8 February, 05:41
Find the zeros of y = 3x^2+3x
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Abel Mack
8 February, 05:43
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The zeros of y = 3x^2+3x means to solve for the values of x when y = 0
y = 3x² + 3x = 0
y = 3x²+3x = 0
3x²+3x = 0 Factorize
3x (x + 1) = 0
3x = 0, or (x + 1) = 0
From 3x = 0, x = 0/3 = 0
From (x + 1) = 0, x = 0 - 1 = - 1.
Therefore the zeros are 0 and - 1.
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