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26 July, 14:25

The perimeter of a rectangle is 86 cm. twice the width exceeds the length by 2cm. write a system and solve to find the dimensions of the rectangle.

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  1. 26 July, 14:26
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    There are two equation of the system

    (1) The perimeter

    2 (w + l) = p

    2 (w + l) = 86

    (2) The length and the width

    2w = l + 2

    From the second equation

    2w = l + 2

    l + 2 = 2w

    l = 2w - 2

    Subtitute l with 2w - 2 in the first equation to find the width

    2 (w + l) = 86

    2 (w + 2w - 2) = 86

    2 (3w - 2) = 86

    6w - 4 = 86

    6w = 90

    w = 15

    Now, find the length by subtituting w with 15

    l = 2w - 2

    l = 2 (15) - 2

    l = 30 - 2

    l = 28

    The dimension of the rectangle

    length = 28 cm

    width = 15 cm
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