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Find each product

(8k+7) (6k+1)

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  1. Today, 05:45
    0
    Given,

    first term a₁ = k

    General term;

    a_{n} = 2a_{n-1}

    Hence, third term (n = 3);

    a_{3} = 2 a_{3-1} = 2a_{2} = 2 * (2a_{2-1}) = 4a_{1} = 4k

    Hence, the answer is B: 4k.
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