A golfball is hit from ground level with an initial vertical velocity of 80 ft/s. Use the function h (t) = - 16t2 + v0t + h0, where h (t) is the height of a golfball hit with initial vertical velocity v0 from initial height h0 after t seconds in the air, to find the time at which the golfball will hit the ground.

Question

Dakota Frye

Mathematics

14 March, 15:54

A golfball is hit from ground level with an initial vertical velocity of 80 ft/s. Use the function h (t) = - 16t2 + v0t + h0, where h (t) is the height of a golfball hit with initial vertical velocity v0 from initial height h0 after t seconds in the air, to find the time at which the golfball will hit the ground.

+2

Answers (1)

Know the Answer?

Cristina Mitchell · Answer 1

Step-by-step explanation:

ball is hit from the ground level i. e h0=0

initial velocity=80

when the ball hits the ground it's height from the ground=0

substitute the data in the above function

0=-16t^2+80*t+0

t=0 is a solution but it is at the beginning of the projection

16t=80

t=5