Find three consecutive even integers such that their sum is 50 more than the largest integer

This is how I'd solve it:

1st no. = 2x (2x) + (2x+2) + (2x+4) = (2x+4) + 50

2nd no. = 2x+2 6x+6=2x+54

3rd no. = 2x+4 4x=48

x=12

Substitute the x value, and your numbers are 24, 26, and 28. To check: their sum (78) is 50 more than the largest integer (28).