Ask Question
7 February, 14:13

7) Solve the following system of equations below algebraically using substitution.

8x - 4y = 7

x + y = 8

+1
Answers (1)
  1. 7 February, 14:18
    0
    x = 3.25

    y = 4.75

    Step-by-step explanation:

    In order to Solve the following system of equations below algebraically using substitution method we say that;

    let;

    8x - 4y = 7 ... equation 1

    x + y = 8 ... equation 2

    from equation2

    x + y = 8 ... equation 2

    x = 8 - y ... equation 3

    substitute for x in equation 1

    8x - 4y = 7 ... equation 1

    8 (8-y) - 4y = 7

    64-8y-4y=7

    64-12y=7

    collect the like terms

    64-7 = 12y

    57 = 12y

    divide both sides by the coefficient of y which is 12

    57/12 = 12y/12

    4.75 = y

    y = 4.75

    put y = 4.75 in equation 3

    x = 8 - y ... equation 3

    x = 8 - 4.75

    x = 3.25

    to check if your answer is correct, put the value of x and y in either equation 1 or 2

    from equation 2

    x + y = 8 ... equation 2

    3.25 + 4.75 = 8

    8=8 ... proved
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “7) Solve the following system of equations below algebraically using substitution. 8x - 4y = 7 x + y = 8 ...” in 📗 Mathematics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers